NYCPHP Meetup

[Nasir Zubair]

Try this:

$name = $_FILES['name']['name'];

The first "['name']" is the name of your file field. The second 'name' is
for accessing the name of uploaded file.

http://www.php.net/manual/en/features.file-upload.php

- Nasir

> -----Original Message-----
> From: Michael Southwell [mailto:southwell at dneba.com] 
> Sent: Wednesday, December 10, 2003 6:18 PM
> To: talk at lists.nyphp.org
> Subject: [nycphp-talk] need help with input type="file"
> 
> 
> The following works perfectly if name is input type="text" 
> but doesn't 
> return anything if type="file," although the browse box is 
> created and 
> works.  What (no doubt something simple) am I missing?
> ------------------------
> <?php
> $execute=$_POST[execute];
> 
> if (!isset($execute)){ //first time through
>    WriteForm();
>    }
> else {  //here from post
>    $name=$_POST[name];
>    echo "The submitted filename is ".$name;
>    }
> 
> function WriteForm(){
>    global $name;
> ?>
>    <form method="post" enctype="multipart/form-data" 
> action="browsebox.php">
>      <input type="hidden" name="execute" value="true" />
>      Filename:<br />
>      <input type="file" name="name" value="<?=$name; ?>" 
> size="75" /><br />
>      <br />
>      <input type="submit" value="Submit filename" />
>    </form>
> <?php
> }
> ?>
> 
> 
> Michael G. Southwell =================================
> DNEBA Enterprises
> 81 South Road
> Bloomingdale, NJ 07403-1419
> 973/492-7873 (voice and fax)
> southwell at dneba.com
> http://www.dneba.com 
> ======================================================
> 
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