[nycphp-talk] Output name of Variable
jim at nettmedia.com
Mon Feb 10 13:56:22 EST 2003
First off, this won't work because $number_of_rows is not declared inside
the function, but that's easily fixed.
Secondly, it seems like a silly way to do it. Why doesn't print_r() just
print the name of the variable? If it's sole purpose as a function is to
print out information about a variable, why not just print the name, too?
Obviously, I can and have worked around it for a long time. It just seems
like it should have been added over the years.
<jim at nettmedia.com>
Nettmedia, Senior Developer
345 Seventh Ave., 24th Floor.
New York, NY 10001
Tel. 212.629.0004 x 131
On 2/10/03 1:44 PM, "Chris Shiflett" <shiflett at php.net> wrote:
> --- Jim Musil <jim at nettmedia.com> wrote:
>> And I wanted to have my output be
>> $number_of_rows: 5
> function bug($var_name)
> echo '$' . $var_name . ': ';
> echo '<pre>';
> echo '</pre>';
> --- Unsubscribe at http://nyphp.org/list/ ---
More information about the talk