NYCPHP Meetup

[Alberto dos Santos]

You must set the value on the input.

 while( $row = mysql_fetch_array( $category ) )
{
 echo(
    "<tr><td>" .$row['expenses_cat_desc'] ."</td><td><input type=text
name=expense_cat value=" . $row['expenses_cat_number'] . " /></td></tr>");
}

And learn your syntax too...

On 13/04/06, Linux Rocks <linux_rocks1 at yahoo.com> wrote:
>
> Hello all:
>
> I am having a problem trying to get a text field get
> its name in a while loop like this expense_cat1,
> expense_cat2 ... etc. here's a snip of the code:
>
> while( $row = mysql_fetch_array( $category ) )
> {
>   echo( "<tr><td>" . $row['expenses_cat_desc'] .
>        "</td><td><input type=text name=expense_cat" .
> $row['expenses_cat_number'] . ("</td></tr>");
>
> }
>
> I pass this to another page and try to print it using
> $_POST['expense_cat1'] and is giving me an empty
> string.
>
> Now, I check phpinfo() and the variable name gets
> created as:
>
> $_POST['expense_cat1</td>']
>
> I don't know how I can get around this. What other
> function can I use to get this working correctly.
>
>
> Thank you in advanced for your help.
>
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--
Alberto dos Santos
Consultor em TI
IT Consultant

http://www.yournway.com
A internet à sua maneira.
The Internet your own way.
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