[nycphp-talk] PHP to ajax variable passing problem
chsnyder at gmail.com
Thu Aug 9 15:46:03 EDT 2007
On 8/9/07, Cliff Hirsch <cliff at pinestream.com> wrote:
> As usual, figured it out minutes after my post. Answer for the group:
> From: var output = req.responseText;
> To: var output = eval('('+req.responseText+')');
> Better answer — don'tr try to reinvent the wheel. Yeah but we can't help
> ourselves. Xajax looks very cool....
Yes eval(), which always makes me a little queasy, even though I know
it's relatively safe. I wonder how many years we'll be waiting for a
true json_decode() function to make it into general circulation?
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