NYCPHP Meetup

[Aaron Fischer]

Indeed it does.  Sorry!  I was led to believe (by my cs professor)  
that the default behavior when copying an array is that the copied  
array is not a new instance but is tied by pointers to the old array,  
so changes to one would change both of them.  Other people in the  
class are using python and java, and apparently that is the case for  
them as they need to use separate functions to make sure the copy  
created is not tied to the old array.

Down near the bottom of the php.net page on arrays, right before the  
user comments:
You should be aware that array assignment always involves value  
copying. It also means that the internal array pointer used by current 
() and similar functions is reset. You need to use the reference  
operator to copy an array by reference.
http://us2.php.net/manual/en/language.types.array.php

-Aaron

On Feb 25, 2007, at 5:39 PM, Daniel Convissor wrote:

> Aaron:
>
> On Sun, Feb 25, 2007 at 03:47:45PM -0500, Aaron Fischer wrote:
>> I need to copy an array by value, not by reference.  Is there a best
>> way to do this?  Right now I found serialize/unserialize which seems
>> to do the trick.
>
> What ARE you talking about?  Copying by value is the default  
> behavior in
> PHP.
>