NYCPHP Meetup

[Kristina Anderson]

Hi all.  I have a question regarding the below syntax

$result = isset($a['c']) ? $a['c'] : NULL;


This is testing two conditions, first if $a['c'] is set, and then, if $a
['c'] is NULL...correct?

What would $result be if $a['c'] is set but is not NULL?  The same as 
if $a['c'] was not set?  or...?

I've seen similar syntax before, in some code Tedd & I were working 
with a couple of months back...and just want to make sure I fully 
understand what is actually happening with it.

Thanks.

-- Kristina

> On Sun, Aug 17, 2008 at 4:49 PM, Michael B Allen <ioplex at gmail.com> 
wrote:
> > Is it ok to access non-existent array elements?
> >
> > Will accessing an array element using a key that does not exist 
always
> > return NULL?
> 
> it depends on how you have warnings configured. you might be getting
> them in your log, for example... i believe the result of accessing a
> non-existent array element is undefined.
> 
> if i were you, i'd prob'ly ask if it exists first:
> 
> <?php
> 
> $result = isset($a['c']) ? $a['c'] : NULL;
> 
> /** OR **/
> 
> $result = array_key_exists('c', $a) ? $a['c'] : NULL;
> 
> ?>
> 
> see:
> 
> http://us2.php.net/function.isset
> http://us2.php.net/function.array-key-exists
> 
> 
> justin
> -- 
> http://justinhileman.com
> _______________________________________________
> New York PHP Community Talk Mailing List
> http://lists.nyphp.org/mailman/listinfo/talk
> 
> NYPHPCon 2006 Presentations Online
> http://www.nyphpcon.com
> 
> Show Your Participation in New York PHP
> http://www.nyphp.org/show_participation.php
> 
>